if one angle of a parallelogram is 56 more than three times of its adjacent angles then find the measure of all the angles
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Let the adjacent angle be x
The angle is x+56
So,x+56+x=180 as the sum of adjacent angles is 180°
=>2x+56=180
=>2x=124
=>x=62
Therefore, the angles are 62,118,62 and 118
The angle is x+56
So,x+56+x=180 as the sum of adjacent angles is 180°
=>2x+56=180
=>2x=124
=>x=62
Therefore, the angles are 62,118,62 and 118
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