Question

❥ If one angle of a parallelogram is 90° less than twice the smallest angle, then find the measure of each angle??​

Answer 1

$\bf \red{QUESTION:}$

If one angle of a parallelogram is 90° less than twice the smallest angle, then find the measure of each angle??

GIVEN:

One angle of a parallelogram is 90° less than twice the smallest angle.

R.T.F:

The measure of each angle.

SOLUTION:

The angles are x , 2x-90°, x , 2x-90°

Sum of all angles in a quadrilateral is 360°

$x + 2x - 90 + x + 2x - 90 = 360 \\ 6x - 180 = 360 \\ 6x = 540 \\ x = 90$

$\therefore \: x = 90$

$2x - 90 = 2(90) - 90 = 180 - 90 = 90$

All angles of the quadrilateral is 90°.

HOPE THIS HELPS YOU ☺️