Question

if one end of diameter of a circle is (4,6) and the center is (-4,7) then the other end is (a) (-12,8) (b) (8,-12) (c) (8,10) (d) (8,-6)​

Answer 1

Answer:

(a). (- 12, 8)

Step-by-step explanation:

The center of a circle is a midpoint between ends of diameter of a circle.

Coordinates of midpoint are

[($x_{1}$ + $x_{2}$) / 2 , ($y_{1}$ + $y_{2}$) / 2]

$\frac{x+4}{2}$ = - 4 ⇒ x = - 12

$\frac{y+6}{2}$ = 7 ⇒ y = 8

(- 12, 8)

Answer 2

Answer:

(a). (- 12, 8)

Step-by-step explanation:

The center of a circle is a midpoint between ends of diameter of a circle.

Coordinates of midpoint are

[(x_{1}x1 + x_{2}x2 ) / 2 , (y_{1}y1 + y_{2}y2 ) / 2]

\frac{x+4}{2}2x+4 = - 4 ⇒ x = - 12

\frac{y+6}{2}2y+6 = 7 ⇒ y = 8

(- 12, 8)