Question

If one of the zeroof the polynomial 5z 2 +13z-P is reciprocal of the other,then find the value of p?

Answer 1

5z 2 +13z-P=0 Compare given eq: ax^2+bx+c=0 Here a=5,b=13,c=-p Now according to Q's: roots are reciprocal means if one root is x then other will be 1/x .. We know that peoduct of zeros= c/a => -p/5= x(1/x) => p= -5

Answer 2

5z2+13z-p

here
a=5
b=13
c=-p

since the zeroes are reciprocal to each other.

therefore their product must be1 .

=> c/a = 1
=> -p/a = 1
=> -p = 5
=> p= -5

therefore the value of p is -5


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