Question

If one of the zeros of the quadratic polynomial ax2 bx c is 0 then the other zero is

Answer 1

Answer:

$\beta =\frac{-b}{a}$

Step-by-step explanation:

$Given \ p(x)=ax^{2} +bx+c\\\\\alpha =0\\\\we \ know \ that \ \alpha +\beta =\frac{-b}{a} \\\\putting \ value \ of \alpha =0 \ here\\\\0+\beta =\frac{-b}{a} \\\\\beta =\frac{-b}a}$

Answer 2

Answer:

The other zeros = -b/a

Step-by-step explanation:

Here,

ax²+bx+c and one of zeros =0

let other zero = Alpha

And we know by relationship between zeros and coefficient,

Alpha+0= -b/a

Alpha= -b/a

so, the other zeros= -b/a.