Question

If one root of equation X2+Kx+3=0is 1 find the value of k
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Answer 1

Answer:

k=-4

Step-by-step explanation:

$x^{2} +kx+3=0$

put 1 in place of x

$(1)^{2}+k(1)+3=0$

$1+k+3=0\\k+4=0\\k=0-4\\k=-4$