Question

If one root of quadratic equation x^2-ax+b=0 is twice the square of other,show that b+4b^2+6ab=2a^3

Answer 1

one root -£
another root -€^2

b+4b^2+6ab=2a^3
sum= -b/a
= -4
product= c/a
=6

Quad poly.
x^2-(sum of zeros)x + (product of zeros)
x^2+4x+6
£=-b/a= -4
€=c/a=6