If one root of quadratic equation x^2-ax+b=0 is twice the square of other,show that b+4b^2+6ab=2a^3
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one root -£
another root -€^2
b+4b^2+6ab=2a^3
sum= -b/a
= -4
product= c/a
=6
Quad poly.
x^2-(sum of zeros)x + (product of zeros)
x^2+4x+6
£=-b/a= -4
€=c/a=6
another root -€^2
b+4b^2+6ab=2a^3
sum= -b/a
= -4
product= c/a
=6
Quad poly.
x^2-(sum of zeros)x + (product of zeros)
x^2+4x+6
£=-b/a= -4
€=c/a=6
armathure:
I want the proof.
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