if one root of the equation 2x^2-5x+k =0 be twice the other, find the value of k.
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Let two roots be a and b of f(x) = 2x²-5x+k = 0
A/q a= 2b
Sum of roots = a + b = 2b + b = 3b = -(-5)/2 = 5/2 ⇒ b = 5/6
Products of roots = ab = k/2 ⇒ 2b .b = 2b² = 2 (5/6)² = 2 x 25/36 = 25/18 = k/2
k = 25/9
Hope my answer is correct.
A/q a= 2b
Sum of roots = a + b = 2b + b = 3b = -(-5)/2 = 5/2 ⇒ b = 5/6
Products of roots = ab = k/2 ⇒ 2b .b = 2b² = 2 (5/6)² = 2 x 25/36 = 25/18 = k/2
k = 25/9
Hope my answer is correct.
parisakura98pari:
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