The side of a square exceeds the side of another square by 4cm and the sum of the areas of the two squares is 400sq.cm.Find the dimensions of the squares.
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Let the side of the smaller square be x cm.
Side of the larger square = Side of the smaller square + 4 cm
∴ Side of the larger square = (x + 4) cm
Given, Area of the smaller square + Area of the larger square = 400 cm2
Side of the smaller square = 12 cm
Side of the larger square = (x + 4) cm = (12 + 4) cm = 16 cm
Side of the larger square = Side of the smaller square + 4 cm
∴ Side of the larger square = (x + 4) cm
Given, Area of the smaller square + Area of the larger square = 400 cm2
Side of the smaller square = 12 cm
Side of the larger square = (x + 4) cm = (12 + 4) cm = 16 cm
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