Question

if one root of the equation ax²+bx+c=0 is twice of the other then let us know that, 2b²=9ac​

Answer 1

Answer:

Let a,ß are the two zeros of the

polynomial ax²+bx+c

Then, atB=-b/a and aß=c/a

By the given condition, B-2a

, a+2a=-b/a

or, 3a--b/a

or, a--b/3a --(1) and

a.2a=c/a

or, 2a²=c/a

or, a²=c/2a

or, (b/3a)²=c/2a [using (1)]

or, b²/9a²=c/2a

or, b²/9a=c/2

or, 2b²-9ac

(Proved)