If one root of the quadratic equation 6 x square minus x minus k is equal to zero is 2/3, then find the value of k
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Answered by
166
Hi !!
Here is your answer :
P( x ) = 6x² - x - k .
It is given that the one zero of the given polynomial is 2/3.
Substitute the value of X = 2/3.
P ( 2/3) = 0
6 × (2/3)² - 2/3 - k = 0
6 × 4 / 9 - 2/3 - k = 0
2 × 4 / 3 - 2/3 - k = 0
8 / 3 - 2/3 - k = 0
8 - 2 - 3k = 0
6 -3k = 0
-3k = -6
k = -6/-3
k = 2
☺ Hope it will help you ☺
By SaniyaAnwar
Here is your answer :
P( x ) = 6x² - x - k .
It is given that the one zero of the given polynomial is 2/3.
Substitute the value of X = 2/3.
P ( 2/3) = 0
6 × (2/3)² - 2/3 - k = 0
6 × 4 / 9 - 2/3 - k = 0
2 × 4 / 3 - 2/3 - k = 0
8 / 3 - 2/3 - k = 0
8 - 2 - 3k = 0
6 -3k = 0
-3k = -6
k = -6/-3
k = 2
☺ Hope it will help you ☺
pradeepthamaheswaren:
thank u:)
Answered by
65
Hey mate
Here is your answer in image
Here is your answer in image
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really neat
thank u :)
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