Question

If one root of the quadratic equation2xsquare+x+k=0is-1/3 then find the vlaue of k​

Answer 1

SOLUTION:-

Given:

Quadratic equation;

2x² + x + k=0

⚫One root of the equation = -1/3

Therefore,

$= > 2( - \frac{1}{3}) {}^{2} + ( - \frac{1}{3} ) + k = 0 \\ \\ = > 2( \frac{1}{9} ) - \frac{1}{3} + k = 0 \\ \\ = > \frac{2}{9} - \frac{1}{3} + k = 0 \\ \\ = > \frac{2 - 3}{9} + k = 0 \\ \\ = > \frac{ - 1}{9} + k = 0 \\ \\ = > k = \frac{1}{9}$

Thus,

The value of k is 1/9.

Hope it helps ☺️