If one zero of 4x²-9-8kx is negative of the other find k.
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Hello user☺☺
Since, the zeroes of 4x²-9-8kx are negative of each other.
So, lets assume one of them to be x
then, other will be -x
Now, using the zeroes-coefficient relation, we have
x-x = -(-8k)/4
8k/4 = 0
k = 0.
Hope this will help☺☺
Since, the zeroes of 4x²-9-8kx are negative of each other.
So, lets assume one of them to be x
then, other will be -x
Now, using the zeroes-coefficient relation, we have
x-x = -(-8k)/4
8k/4 = 0
k = 0.
Hope this will help☺☺
nautiyaladitya7:
How can you solve this questions
Answered by
1
Step-by-step explanation:
Answer :-
→ k = 0 .
Step-by-step explanation :- ----
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
Hence, it is solved.
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