Question

If one zero of a poly (a^2+a)x^2+13x+6a is the reciprocal of the other, find value of a

Answer 1

here so 6a/a2+a=1
6=a+1
a=5

Answer 2

(a^2+a)x^2+13x+6a=0

product of roots of quadratic equation in the form, ax^2+bx+c=0 is c/a

product of roots(in this case, reciprocals)=1

(6a)/(a^2+a)=1

(6a)/a(a+1) =1

6/(a+1) =1

6= a+1

5=a

hope it helps u