Question

If one zero of quadratic polynomial [(k²+9)x²+13x+6k] is reciprocal of the other , find k

Answer 1

the zeros of the polynomial are reciprocal of each other so their product will be 1
product of zeros = 6k/k^2+9
1*(k^2+9)=6k
k^2-6k+9=0
(k-3)^2=0
k=3