Question

If only 2% of the main current is to be passed through a galvanometer of resistance G, then the resistance of shunt will be [MP PMT/PET 1998]
A) \frac{G}{50} B) \frac{G}{49} C) 50\,G D) 49\,G

Answer 1

Let total current through the circuit be I.
Then, 0.02I current is to be passed through galvanometer of resistance G.
Let the resistance of shunt is Rs .
∵ Shunt are in parallel combination with Galvanometer.
∴ 0.02I × G = (1 - 0.02)I × Rs
⇒0.02G = 0.98 × Rs
⇒Rs = 0.02G/0.98 = G/49

Hence answer is G/49

Answer 2

Answer:

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