If P(A) = 0.4 P(B) = 0.5 and P(A∩B) = 0.2 then P(B/A) is
(a) 1/2
(b) 1/3
(c) 4/5
(d) 2/5
Answers
Answered by
0
If P(A) = 0.4 P(B) = 0.5 and P(A∩B) = 0.2 then P(B/A) is
(a) 1/2
(b) 1/3
(c) 4/5
(d) 2/
(a) 1/2
(b) 1/3
(c) 4/5
(d) 2/
Answered by
0
Hi ,
******************************************
If A and B are any two events in S
P( A and B ) = P( A ) P( B/A )
If P( A ) ≠ 0 .
********************************************,
Now ,
It is given that ,
P( A ) = 0.4,
P( B ) = 0.5 ,
P( A and B ) = 0.2
P( B/A ) = P( A and B )/P( A )
= 0.2 / 0.4
= 1/2
Therefore ,
P( B/A ) = 1/2
Option ( a ) is correct.
I hope this helps you.
: )
******************************************
If A and B are any two events in S
P( A and B ) = P( A ) P( B/A )
If P( A ) ≠ 0 .
********************************************,
Now ,
It is given that ,
P( A ) = 0.4,
P( B ) = 0.5 ,
P( A and B ) = 0.2
P( B/A ) = P( A and B )/P( A )
= 0.2 / 0.4
= 1/2
Therefore ,
P( B/A ) = 1/2
Option ( a ) is correct.
I hope this helps you.
: )
Similar questions