Question

if p=a+b and q=ab ,then the factors of x^2+px+q is

Answer 1

Answer:(x+a)(x+b)

Step-by-step explanation:

x^2+ax+bx+ab

x(x+a)+b(x+a)

(X+a)(x+b)

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Answer 2

The factors of the polynomial are

$(x+a)\text{ and }(x+b)$

Step-by-step explanation:

We are given the following in the question:

$p = a + b\\q = ab$

We have to find the factors of the polynomial:

$x^2+px+q = \\x^2 + (a+b)x + ab = 0\\x^2 + ax + bx + ab = 0\\x(x+a)+b(x+a)=0\\(x+a)(x+b) = 0$

Thus, the factors of the polynomial are

$(x+a)\text{ and }(x+b)$

#Learnmore

If (x+1) is a factor of polynomial x^2 +px +q and p+q=3 then the value of p and q are?

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