Question

If P(A) = $\frac{1}{2}$, P(B) = 0, then P(A|B) is
(A) 0
(B)$\frac{1}{2}$
(C) not defined
(D) 1

Answer 1

Answer:

C

Step-by-step explanation:

P ( A | B ) = P ( A ∩ B ) / P ( B )

Since P(B) = 0, this fraction is undefined.