Question

if p and q are the roots of equation X square - 3 x + 2 is equals to zero find the value of 1 by p minus 1 by q

Answer 1

Answer:

It must help u......

Steps r also very simple

Answer 2

Step-by-step explanation:

x² - 3x + 2 = 0

x² - x - 2x + 2

x(x-1)-2(x-1)

(x-1)(x-2)

x = 1

and

x = 2

if p and q are the roots of equation x² - 3x + 2

Then,

p = 1

and

q = 2

Then, the Value of 1/p - 1/q is

$\frac{1}{p} - \frac{1}{q} \\ \\ \frac{q - p}{pq} \\ \\ \frac{2 - 1}{2 \times 1} \\ \\ \frac{1}{2} \\ \\ = 0.5$

The Value of p and q may be

p = 2

and

q = 1

Then , the Value of 1/p - 1/q is

$\frac{1}{p} - \frac{1}{q} \\ \\ \frac{q - p}{pq} \\ \\ \frac{1 - 2}{2 \times 1} \\ \\ \frac{ - 1}{2} \\ \\ - 0.5$