if p and q are the zeroes of polynomial f(x) = 2x²-7x+3 find the value of p²+q²
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3
the zeros of the polynomial are 1/2 and 3
(1/2)²+(3)²
1+9=10
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0
Answer:
2x²-7x+3=0
p²+q²= 25+16
= 41
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