Question

If p and q are the zeroes of the quadratic polynomial p (x)=x^2-k (x-1)-a and if (p+1)(q-1)=0,find the value of 'a'

Answer 1

Answer:

x2 - p(x + 1) - c  

= x2 - px - p - c  

 

Comparing with ax2 + bx + c, we get

a= 1 , b = -p and c = - p - c

 

α and β are the zeroes of the given polynomial.

 

→ p + q = -b/a = -(-p)/1 = p

and pq = c/a = -p - c / 1 = -p - c

 

To find: (p + 1)(q + 1)  

(q + 1)(p + 1) = pq + p + q + 1

                     = - p - c + p + 1  

                     = 1 - c