If P(B‘) = 0.65, P(A ∪ B) = 0.85 and A and B are independent events, then find P(A)
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A and B are independent events that means they are two disjoint sets.
So, A intersection B = 0
G T, P(AUB)= 0.85
P(B')= P (not B)
= 1-P (B)
P(B)= I -P (B')
= 1-0.65
= 0.35
WKT, P (AUB) =P(A)+ P(B)- P (A int B)
0.85= P (A)+0.35-0
P (A)=0.85-0.35
=0.5
⇒ P (A)= 0.5
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