if p is a prime number and p2+1 is also a prime number,what is the remainder while dividing 5632 by p3+1
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Answer:7
Step-by-step explanation:
odd*odd gives an odd number
Similarly even*even gives an even number
Now p is prime
Since p²+1 is prime therefore p² must be even(since adding 1 will make it odd and prime no. Are odd apart from 2)
Since p² is even p must be even
Only even prime no. is= 2
Therefore, p = 2
Now p³+1 = 9
5632 MOD 9 will be same as (5+6+3+2) MOD 9 thus 16 MOD 9 = 7
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