Question

if P is mid point of ab and D is mid point of PB then using suitable axiom prove that BD=1/4 AB​

Answer 1

Step-by-step explanation:

Answer:

\bf \underline{The\ original\ number\ is\ 92.}

The original number is 92.

Step-by-step explanation:

Let the digit at tens and units place be x and y respectively.

Amd the number be (10x+y)

Given

Product of digit is 18.

So,

ATE, xy=18

or y=18/x -(1)

Also, when 63 is subtracted from the number, the digits interchange their place.

So, the number formed by interchanging the digits is (10y+x)

ATE,

(10x+y)-63=(10y+x)

10x-x+y-10y=63

9x-9y=63

9(x-y)=63

x-y=7 -(2)

Using y=18/x in eq. (2)

\begin{lgathered}x-\frac{18}{x}=7\\ \\ \implies \rm x^2-18=7\\ \\ \implies \rm \frac{x^2-18}{x}=7\\ \\ \implies \rm x^2-7x-18=0\\ \\ \implies \rm x^2-9x+2x-18=0\\ \\ \implies \rm x(x-9) 2(x-9)=0\\ \\ \implies \rm (x+2) (x-9)=0\\ \\ \implies \bf x=-2\ or\ \bf 9 \\ \rm But\ digit\ can't\ be\ negative.\\ \therefore \bf x=9\end{lgathered}

x−

x

18

=7

⟹x

2

−18=7

⟹

x

x

2

−18

=7

⟹x

2

−7x−18=0

⟹x

2

−9x+2x−18=0

⟹x(x−9)2(x−9)=0

⟹(x+2)(x−9)=0

⟹x=−2 or 9

But digit can

′

t be negative.

∴x=9

Putting x=9 in eq. (1)

9y=18

y=2

So, the number is (10×9+2)=90+2=92