Math, asked by bharatolajt369741, 1 year ago

if p/q=(3/2)-2÷(6/7)0 find the value of (p/q)^-3

Answers

Answered by Agastya0606
41

Given: p/q=(3/2)^-2 ÷ (6/7)^0

To find: The value of (p/q)^-3

Solution:

  • Now we have given the value of p/q as (3/2)^-2 ÷ (6/7)^0
  • So simplifying it, we get:

             p/q = (3/2)^-2 / 1        

             as anything raised to power 0 is always 1.

  • So, p/q = (2/3)^2 = 4/9

  • Now we have to find the value of  (p/q)^-3.
  • We can rewrite it as (q/p)^3.
  • Now putting value in it, we get:

              (q/p)^3 = (9/4)^3

                         = 729 / 64

Answer:

             So the value of (p/q)^-3 is 729 / 64.

Answered by devakumar99
2

Answer:

If

= (

3

2

)

−2 ÷ (

6

7

)

0

, find the value of (

)

−3

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