if p,q&r are interior angles of a triangle PQR ,then show that sec(p+r/2)=cosec(r/2)
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HERE IS YOUR ANSWER...
Since, we know that, p + q + r = 180°
=> p + r = 180° - q
Now,
LHS = sec(p+r/2)
= sec(180°-q/2)
= sec (90°-q/2)
= cosec q/2 = RHS proved.
NOTE :- Your question is wrong. It should be cosec q/2.
# GUDIYA...
HOPE IT HELPS !! ☺☺☺
HERE IS YOUR ANSWER...
Since, we know that, p + q + r = 180°
=> p + r = 180° - q
Now,
LHS = sec(p+r/2)
= sec(180°-q/2)
= sec (90°-q/2)
= cosec q/2 = RHS proved.
NOTE :- Your question is wrong. It should be cosec q/2.
# GUDIYA...
HOPE IT HELPS !! ☺☺☺
yatheendra:
thank u for correcting my question & giving an useful answer
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1
Answer:
here is your answer our questions are different but method is same
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