Math, asked by amansuresh250, 9 months ago

If p + q + r = 9 then (3-p)^3 + (3-q)^3 + (3–r)^3 is :-
a) 3(3-p)(3—q)(3–r) b) 0
c) 1.
d) -3(3-p)(3—9)(3-r)​

Answers

Answered by bhumikalalkiya
1

Answer:

a.3(3-p)(3-q)(3-r)

Step-by-step explanation:

p^3+q^3+r^3= 3pqr+(p+q+r)(p^2+q^2+r^2-pq-qr-pr)

by this (p+q+r) = 0

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