Question

If p(q-r)x2+ q(r-p)x + r(p-q) = 0 has equal roots

Answer 1

if it has equal roots

discriminant =0

b^2= 4ac

[q(r-p)]^2= 4*p(q-r)*r(p-q)
q2(r2-2rp+p2)= 4pr(pq-q2-pr+rq)

q2r2-2pq2r+p2q2 = 4p2qr- 4pq2r-4p2r2+4pqr2