Math, asked by sumit7794, 1 year ago

if p=t + 4t^-1/2 then find the value of p, when t=64

Answers

Answered by Cutiepie93
7
Hello friends!!

Here is your answer :

 \\  =  > p = t + 4 {t}^{  \frac{ - 1}{2} }



Given, t = 64.

So for finding the value of p we have to put the value of t.

 \\  =   > p = 64 +  4{(64)}^{  \frac{ - 1}{2} }

We can write 64 as 8² because 8 × 8 = 64.

 \\  =  > p = 64  +  4  {( {8}^{2}) }^{ \frac{ - 1}{2} }


 \\  =  > p = 64 + 4 {( 8)}^{2 \times \frac{ - 1}{2} }


 \\  =  > p = 64 + 4 {( 8)}^{ - 1}


 \\  = > p = 64 + 4 \times  \frac{1}{8}


 \\  =  > p = 64 +  \frac{1}{2}


 \\  =  > p =  \frac{128 + 1}{2}

 \\  =  > p =  \frac{129}{2}


 =  > p = 64.5



Therefore, your answer is 64.5

Hope it helps you

^_^

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