Question

if p=t + 4t^-1/2 then find the value of p, when t=64

Answer 1

Hello friends!!

Here is your answer :

$\\ = > p = t + 4 {t}^{ \frac{ - 1}{2} }$



Given, t = 64.

So for finding the value of p we have to put the value of t.

$\\ = > p = 64 + 4{(64)}^{ \frac{ - 1}{2} }$

We can write 64 as 8² because 8 × 8 = 64.

$\\ = > p = 64 + 4 {( {8}^{2}) }^{ \frac{ - 1}{2} }$


$\\ = > p = 64 + 4 {( 8)}^{2 \times \frac{ - 1}{2} }$


$\\ = > p = 64 + 4 {( 8)}^{ - 1}$


$\\ = > p = 64 + 4 \times \frac{1}{8}$


$\\ = > p = 64 + \frac{1}{2}$


$\\ = > p = \frac{128 + 1}{2}$

$\\ = > p = \frac{129}{2}$


$= > p = 64.5$



Therefore, your answer is 64.5

Hope it helps you

^_^