if p(t) =t^3+3,then find the value of p(0)÷p(1)+p(2)
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p(0)=0³+3=3,
p(1)=1³+3=1+3=4,
p(2)=2³+3=8+3=11,
then
p(1)+p(2)=4+11=15,
therefore
p(0)÷[p(1)+p(2)],
3/15,
1/5
p(1)=1³+3=1+3=4,
p(2)=2³+3=8+3=11,
then
p(1)+p(2)=4+11=15,
therefore
p(0)÷[p(1)+p(2)],
3/15,
1/5
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