Question

If P(x) =3x² + 5x+7 then find P(1)+P(-1)/P(-2) + P (3)​

Answer 1

Answer:

78

Step-by-step explanation:

p(x) = 3x^2+5x+7

p(1)= 3*1^2 + 5*1+7= 15

p(-1)= 3*(-1)^2 +5(-1) + 7= 5

p(-2) = 3(-2)^2 + 5(-2)+7 = 9

p(3) = 3(3)^2 + 5(3)+7 = 49

Now,

p(1)+p(-1)+p(-2)+p(3) = 15+5+9+49= 78

Answer 2

The correct answer is "581/9".

Step-by-step explanation:

$The \ given \ equation \ is:\\\\P(x)=3x^2+5x+7\\\\P(1)+\frac{P(-1)}{P(-2)}+P(3)=?\\\\ Now,\\\\P(1)=3(1)^2+5(1)+7\\P(1)=3+5+7\\P(1)=15\\\\P(-1)=3(-1)^2+5(-1)+7\\P(-1)=3-5+7\\P(-1)=5\\\\P(-2)=3(-2)^2+5(-2)+7\\P(-2)=3(4)-10+7\\P(-2)=12-10+7\\P(-2)=9\\\\P(3)=3(3)^2+5(3)+7\\\\P(3)=3(9)+15+7\\P(3)=27+15+7\\P(3)=49\\\\=P(1)+\frac{P(-1)}{P(-2)}+P(3)\\\\=15+\frac{5}{9}+49\\ \\On \ taking \ LCM,we \ get\\\\=\frac{135+5+441}{9}\\\\=\frac{581}{9}$

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