Question

If p(x)=ax^2+bx+c and a+c=b, then one of the zeroes of p(x) is,

a. 4/3
b. -4/3
c. 2/3
d. -2/3

Explain procedure also.

Answer 1

$p( - 1) = a - b + c$

$= 0 \\ so \: - 1is \: a \: zero \: of \: p(x)$

$the \: otherzero \: is \: \frac{ - c}{a}$

the question needs to have more information to find the second Zero