Question

if p(x)=(x-1)(x+1) then the value of p(0) p(1) p(2) ate respectively ​

Answer 1

Answer:

p(0)= (0-1)(0+1)

p(0)=(-1)(1)

p(0)=-1

p(1)=(1-1)(1+1)

p(1)=(0)(2)

p(1)=0

p(2)=(2-1)(2+1)

p(2)=(1)(3)

p(2)=3

Answer 2

Step-by-step explanation:

if p(x)=(x-1)(x+1)

we know that (x^2 - 1^2) = (x+1)(x-1).

so first subsitude the value of x=0

0^2 - 1^2 = 1.

now subsitude x=1

1^2 - 1^2 = 2.

now subsitude x=2.

2^2 - 1^2 = 5.

HENCE:-

p(0)=1.

p(1)=2.

p(2)=5.