Question

if p(x)=x²-5x+6 then the difference of the zeros of p(x) is​

Answer 1

Answer:

5 answer

Step-by-step explanation:

p(0)=0-5(0)+6 =0+5=5

Answer 2

Answer:

$x {}^{2} - 5x + 6 = 0 \\ x { }^{2} + x - 6x + 6 \\ x(x + 1) - 6(x + 1) \\ (x + 1)(x - 6) \\ x + 1 = 0 \\ x = - 1 \\ \\ x - 6 = 0 \\ x = 6 \\ \\ difference \: of \: zeros = - 1 - 6 \\ = - 7$