Question

if p(x)=x³+x²-9x-9, then find p(0), p(3), p(-3), p(-1)

Answer 1

Answer:

Step-by-step explanation:

P(x)=x^3 +x^2-9x-9

P(0) =0+0-0-9

=-9

P(3)=27+9-27-9

=0

P(-3)=-27+9+27-9

=0

P(-1)=-1+1+9-9

=0