Question

If p(y) = 2y3 – 8y2 + 19y + 2 then find p(3).​

Answer 1

Given :

• p(y) = 2y³ – 8y²+ 19y + 2

To find :

• p(3)

Solution :

To find p(3) put y = 3 in p(y) = 2y³ – 8y²+ 19y + 2

=> p(y) = 2y³ – 8y²+ 19y + 2

=> p(3) = 2(3)³ – 8(3)²+ 19(3) + 2

We know that :- 3³= 27

We know that :- 3³= 27 3² = 9

=> p(3) = (2×27) – (8×9)+ 57 + 2

=> p(3) = 54– 72+ 57 + 2

=> p(3) = 54– 72+ 57 + 2

=> p(3) = 113-72

=> p(3) = 41

Answer : p(3) = 41

Answer 2

Answer:

✦ Given :-

• p(y) = 2y³ - 8y² + 19y + 2

✦ To Find :-

• What is the value of p(3) .

✦ Solution :-

➣ Given : p(y) = 2y³ - 8y² + 19y + 2

⋆ Now we have to take y = 3 we get,

⇒ p(3) = 2(3)³ - 8(3)² + 19(3) + 2

⇒ p(3) = 2 × 3 × 3 × 3 - 8 × 3 × 3 + 57 + 2

⇒ p(3) = 54 - 72 + 59

➠ p(3) = 41

∴ The value of p(3) is 41 .

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