Math, asked by GudduSingh5500, 1 year ago

if p(y) =4+3y-Y2 +5y3, find p(0), p(2) ,p( -1)

Answers

Answered by preeti9578
47

Answer:

Step-by-step explanation:

p(y)=4+3y-y²+5y³

     =5y³-y²+3y+4

p(0)=5y³-y²+3y+4

     =5*(0)³-(0)²+3*0+4

     =5*0-0*3+0+4

     =0-0+0+4

     =4

p(1)=5y³-y²+3y+4

    =5*(1)³-(1)²+3*1+4

    =5*1-1+3+4

    =5-1+7

    =4+7

    =11

p(2)=5y³-y²+3y+4

     =5*(2)³-(2)²+3*2+4

     =5*8-4+6+4

     =40-4+10

     =36+10

     =46

so, p(0)=4 , p(1)=11 , p(2)=46

Answered by abhimanyurawat460
11

Step-by-step explanation:

p(y)=4+3y-y²+5y³

    =5y³-y²+3y+4

p(0)=5y³-y²+3y+4

    =5*(0)³-(0)²+3*0+4

    =5*0-0*3+0+4

    =0-0+0+4

    =4

p(1)=5y³-y²+3y+4

   =5*(1)³-(1)²+3*1+4

   =5*1-1+3+4

   =5-1+7

   =4+7

   =11

p(2)=5y³-y²+3y+4

    =5*(2)³-(2)²+3*2+4

    =5*8-4+6+4

    =40-4+10

    =36+10

    =46

so, p(0)=4 , p(1)=11 , p(2)=46

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