If (p2-q2) sin theta+2pqcos theta=p2-q2 find tan theta
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Answer:
Secθ - (2pq/p² - q²)
Step-by-step explanation:
(p²-q²) sinθ + 2pq cosθ = p²- q²
Divide the LHS and RHS by Cosθ
(p²-q²) Sinθ/Cosθ + 2pq Cosθ/Cosθ = p² - q²/Cosθ
(p² - q²) Tanθ + 2pq = (p² - q²)Secθ
(p² - q²) Tanθ = (p² - q²)Secθ - 2pq
Tanθ = Secθ - (2pq/p² - q²)
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