Question

if perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm what is the area of the quadrilateral

Answer 1

Answer:

Step-by-step explanation:

Let sides of the rhombus be a

So, perimeter of rhombus = 4a =100

Therefore, a=25

Now , we know that diagonals of a rhombus bisect each other at 90° .

( We will now join the diagonals of the rhombus and pick up anyone triangle formed and apply Pythagoras theorem)

So,

25²-24²=(1/2 *d2)²

625-576=(d2/2)²

So, d2*1/2 = 7

Now d2 = 14

Therefore, area of the rhombus = 1/2* d1*d2 = 1/2*48*14 =326.

Hope this helps !!