Question

if perimeter of rectangle is 96 c.m and area is 560 sq.c.m ..then find its length and breadth
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Answer 1

Answer:

20 , 28

Step-by-step explanation: IT IS GIVEN THAT PERIMETER OF THE RECTANGLE IS 96CM . LET LENGTH BE L AND BREADTH BE B.

2(L + b ) = 96

(L + B) = 48

L = 48 - B - (1)

NOW AREA OF THE RECTANGLE  = 560 sq.c.m

LB = 560 - (2)

SUBSTITUTING (1) IN (2) WE HAVE

(48 - B)B = 560

48B - B^2 = 560

B^2 - 48B + 560 = 0

B^2 - 20B - 28B + 560 = 0

B(B-20) - 28(B-20) = 0

(B-20) (B-28) = 0

B = 20 OR B = 28

THE LENGTH OF THE RECTANGLE IS 20CM AND BREADTH IS 28CM RESPECTIVELY.

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