Question

If pressure of
an ideal
gas
is decreased
by 10% isothermally, then its volume
will
(A) decrease by 996
(B) increase by 9%
(C) decrease by 10%
(D) increase by 11.11%​

Answer 1

Answer:

The volume will increase by a factor of 10/9 or about 1.11 when there is a 10% decrease of pressure.

Answer :- (D)

Answer 2

Answer:

Increased by 11%

Explanation

THE ideal gas equation is given by, PV=RT

For a isothermal process, the temperature remains constant. So if pressure decreases so the volume will increase.  

Thus, P1V1=P2V2

i.e.p1/p2=v2/v1

here p2=p1-p1/10=(9p1/10)

i.e.p2/p1=9/10

so, v2/v1=10/9

thus,% increase in volume =[V2-V1/V1]*100

=[(V2/V1)-1]100

=[(10/9)-1]100

=11.1%

​