If Pth
, q
th and rth terms of an A.P. are in G.P. then the common ratio of this G.P. is?
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Answer:
Let first term of the AP = a and common difference = d
pth of an AP= a+(p−1)d
qth of an AP= a+(q−1)d
rth of an AP= a+(r−1)d
are in G.P
Let first term of the GP be x and common ratio be y
then
a+(p−1)d=x........(i)
a+(q−1)d =xy........(ii)
a+(r−1)d=xy² ........(iii)
Subtract (i) from (ii) and get
(q−1)d −(p−1)d=xy−x
→(q−p)d=xy−x......(iv)
Subtract (ii) from (iii) and get
(p−1)d −(r−1)d=xy²−xy =y(xy−x)
→(q−r)d=y(xy−x) .....(v)
divide (v) by (iv) and get
∵ y = q-r/p-q
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