Math, asked by srilakshminarayani1, 5 hours ago

If q = -1 is one root of the equation x2– px-1 = 0 ,then find p

Answers

Answered by priyadharshini23
1

Answer:

x2– px-1 = 0

substituting x =-1

1+p-1 = 0

p=0

Answered by ritushimar8
1

Answer:

p=0

Step-by-step explanation:

x²– px-1

If q = -1 is one root of the equation then x is replaced by -1 and then equation equal to zero.

x²– px-1

put x= -1

(-1)²-p(-1)-1=0

1+p-1=0

p=0

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