Question

if R is an integer betwwn 1&9 , P-R= 2370 what is the value of R , if p is divisble by 4 &9
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Answer 1

Answer:

r=6

GIVEN- P-R= 2370

FIND- value of r

Step-by-step explanation:

p-6=2370

p= 2370+6

p= 2376

sum of digits in p = 2+3+7+6=18

18 is divisible by 9

therefore p is divisible, last two digits of p is divisible by 4 i.e 76 is divisible by 4

therefore p is divisible by 4and 9

FINAL ANSWER- r= 6

#SPJ3

Answer 2

We have to find the value of R.

R lies between (1,9)

Also, given that

$p - r = 2370$

Given that P is divisible by 4 and 9

Divisibility of 4:

A number will be divisible by 4, if last two digits of the number is divisible by 4.

Eg: 2724 is divisible by 4 as its last two digits 24 is divisible by 4.

Divisibility of 9:

A number will be divisible by 9, if sum of all the digits of the number is divisible by 9.

Eg: 6372 is divisible by 9 as the sum of its digits 6+3+7+2=18 and 18 is divisible by 9.

As per the given data, P-R= 2370

P is divisible by 9:

i.e, 2+3+7+0 = 12.

Now, P= 2370+R

For P to be divisible by 9 we need to add 6, so that 12+6=18 and 18 is divisible by 9.

Therefore, take R=6

P= 2370+6

=2376

It is divisible by 9.

Confirmation:

P should be divisible by 4 as well

If R=6, then P= 2376

Last two digits of P are 76 and 76 is divisible by 4.

Hence, R can be taken as 6.

It also lies between the values 1 and 9.

Hence, R=6