if range is taken to be (3π/2,5π/2).find the value of tan ^-1(√3).
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Step-by-step explanation:
tan
−1
3
−cot(−
3
)
∵tan
3
π
=
3
and cot(π−
6
π
)=−
3
tan
−1
3
=
3
π
and
cot
−1
(−
3
)=π−
6
π
tan
−1
3
−cot(−
3
) =
3
π
−(π−
6
π
)
=
3
π
−π+
6
π
=−
2
π
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