Question

If relative decrease in vapour pressure is 0.4 for a solution containing 1 mol Nacl in 3 mol of h2o then % of ionization of nacl is

Answer 1

Answer:

100 percent

Explanation:

RLVP=inb/na+inb

0.4 = i/i+3

solving we get i=2

α=i+1/n+1

Putting i=2 and n=2 we get α=1

therefore alpha*100=100 percent