if resistance of a wire formed by 1.cc of copper be 2.46 ohm. the diameter of wire is 0.32mm, then the specific resistance of wire eill be
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hey mate!
as u know
R =rho l/A
multiplying both numerator and denominator by A you will get..
R =rho V/A^2
where,
V = volume (given 1cc)
A =area
rho =RA^2/V
1mm =0.1cm....
diameter=0.32mm =0.16 ×10^-cm..
Rho =2.46(0.16×0.16×10^-2 ×3.14)^2
rho =1.58 × 10^-6 ohm-cm
as u know
R =rho l/A
multiplying both numerator and denominator by A you will get..
R =rho V/A^2
where,
V = volume (given 1cc)
A =area
rho =RA^2/V
1mm =0.1cm....
diameter=0.32mm =0.16 ×10^-cm..
Rho =2.46(0.16×0.16×10^-2 ×3.14)^2
rho =1.58 × 10^-6 ohm-cm
SayanCR7:
ur status is very nice...
:-))
then answer
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