Question

If resistors 4 ohm,5 ohm, and 6 ohm are connected in series with 5V battery,calculate the total Power consumed by the combination.​

Answer 1

Given - Resistance and voltage

Find - Power

Solution - Power consumed = Voltage²/Resistance

Resistance = 4 + 5 + 6

(As the resistance is connected in series)

Performing addition

Resistance = 15 ohm

Keep the values in formula to find the resistance.

Power = $\frac{{5}^{2} }{15}$

Taking square of numerator

Power = $\frac{25}{15}$

Performing division

Power = $\frac{5}{3}$

Performing division

Power = 1.67 Watts

Hence, the power consumed by the combination is 1.67 Watts

Answer 2

The power consumed by the combination of $4$ ohm, $5$ ohm, and $6$ ohm resistors connected in series with $5V$ battery is $1.67$ Watt.

Given:

$R_{1} =4,R_{2}=5,R_{3}=6$ are connected in series and $V=5$

Then the total equivalent resistance is,

$R_{eq}=R_{1}+R_{2}+R_{3}$

      $=4+5+6$

      $=15$

We know that,

Power,$P=\frac{V^{2} }{R}$.

Then,

$P=\frac{5^{2} }{15}$

$P=\frac{25}{15}$

$P=\frac{5}{3}$

$P=1.67$ Watt

Therefore, the total power consumed by the combination of $4$ ohm, $5$ ohm, and $6$ ohm resistors connected in series with $5V$ battery is $1.67$ Watt.