if root 2 +root 3 /3 root 2 -2 root 3 =a+b root 6 find the value of a and b
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(root 3 + root 2)(root 3 ‑ root 2) (a+b)(a‑b) = a square ‑ b square (root 3 + root 2)(root 3 ‑ root 2) = {root 3} ^2 ‑ {root 2 }^2 = 3‑ 2 (root 3 + root 2)(root 3 ‑ root 2) = 1
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